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Q7. A ship of length 120 m displaces 11750 tonne when floating in sea water of density 1025 kg/m3. The center of gravity is 2m above the center of buoyancy and the waterplane is defined by the following equidistant half-ordinates given in Table Q1:
Station
AP
1
2
3
4
5
6
7
FP
Half-breadth (m)
3.3
6.8
7.6
8.1
8.1
8.0
6.6
2.8
0
Calculate EACH of the following:
(a) The area of the waterplane;
(b) The position of the centroid of the waterplane from midships;
(c) The second moment of area of the waterplane about a transverse axis through the centroid;
(d) The moment to change trim one centimeter (MCT1cm).
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- 09
Q8. A ship 100 m long floats at a draught of 6 m and in this condition the immersed cross-sectional areas and water plane areas are as given below. The equivalent base area (Ab) is required because of the fineness of the bottom shell.
Section
AP
1
2
3
4
5
FP
Immersed cross section area (m2)
12
30
65
80
70
50
0
.
Draught (m)
0
0.6
1.2
2.4
3.6
4.8
6.0
Waterplane area (m2)
Ab
560
720
880
940
1000
1030
Calculate EACH of the following:
(a) The equivalent base area value Ab;
(b) The longitudinal position of the center of buoyancy from midships;
(c) The vertical position of the center of buoyancy above the base.
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Question Set: 2019/JUN (MEO Class II : NAVAL)
Total Questions: 10