- 01
- 02
- 03
- 04
- 2011/JUL/05
- 2011/NOV/04
- 2012/JAN/04
- 2014/JAN/05
- 2014/SEP/04
- 2014/NOV/04
- 2015/JAN/03
- 2015/MAR/03
- 2015/JUN/04
- 2015/AUG/05
- 2015/DEC/04
- 2011/AUG/05
- 2012/DEC/03
- 2016/JAN/02
- 2016/OCT/03
- 2017/SEP/03
- 2017/NOV/02
- 2018/MAR/02
- 2019/JUN/04
- 2019/AUG/01
- 2019/OCT/02
- 2020/MAR/01
- 2020/NOV/04
- 2021/FEB/04
- 2022/JAN/02
- 2022/JUL/01
- 2022/DEC/05
- 2009/JUN/**
- 2009/FEB/**
- 2007/JUL/**
- 2007/JUN/**
- 2007/FEB/**
- 2006/SEP/**
- 2010/NOV/**
- 2010/SEP/**
- 2010/JUL/**
- 2010/JUN/**
- 2010/MAR/**
- 2016/JUN/04
- 2023/MAR/04
- 2023/OCT/05
- 2024/SEP/05
- 05
- 06
- 07
- 08
- 09
- 10
Q8. A ship 100 m long floats at a draught of 6 m and in this condition the immersed cross-sectional areas and water plane areas are as given below. The equivalent base area (Ab) is required because of the fineness of the bottom shell.
Section
AP
1
2
3
4
5
FP
Immersed cross section area (m2)
12
30
65
80
70
50
0
.
Draught (m)
0
0.6
1.2
2.4
3.6
4.8
6.0
Waterplane area (m2)
Ab
560
720
880
940
1000
1030
Calculate EACH of the following:
(a) The equivalent base area value Ab;
(b) The longitudinal position of the center of buoyancy from midships;
(c) The vertical position of the center of buoyancy above the base.
Question Subject: MEO Class II : NAVAL (2021/FEB)
Total Questions: 10